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4.9x^2-24x-10=0
a = 4.9; b = -24; c = -10;
Δ = b2-4ac
Δ = -242-4·4.9·(-10)
Δ = 772
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{772}=\sqrt{4*193}=\sqrt{4}*\sqrt{193}=2\sqrt{193}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-2\sqrt{193}}{2*4.9}=\frac{24-2\sqrt{193}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+2\sqrt{193}}{2*4.9}=\frac{24+2\sqrt{193}}{9.8} $
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